Vidyaranyapura, Bangalore, India - 560097.
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Telugu Mother Tongue (Native)
IETE NewDelhi 2007
Bachelor of Engineering (B.E.)
Kuvempu University 2010
MSC In Mathematics
Vidyaranyapura, Bangalore, India - 560097
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
10
Board
CBSE, IGCSE, ISC/ICSE, State, International Baccalaureate
IB Subjects taught
Physics, Mathematics
ISC/ICSE Subjects taught
Mathematics, Computer Science
CBSE Subjects taught
Physics, Mathematics, Computer Science
IGCSE Subjects taught
Mathematics
Experience in School or College
Since 2008 to till date i am teaching for PUC(CBSE) board level ,IITJEE Mains ,NEET Physics .i brought 100% results in my 10 year teaching .
Taught in School or College
Yes
State Syllabus Subjects taught
Education, Physics, Computer Science, Electronics, Mathematics, French, Telugu
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
5
Engineering Entrance Exams
IIT JEE Coaching Classes
IITJEE Coaching
IIT JEE Mains Coaching, IIT JEE Crash Course
Type of class
Crash Course, Regular Classes
IIT-JEE Subjects
Maths
1. Which school boards of Class 12 do you teach for?
CBSE, IGCSE, ISC/ICSE and others
2. Have you ever taught in any School or College?
Yes
3. Which classes do you teach?
I teach Class 12 Tuition and Engineering Entrance Coaching Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 10 years.
Answered on 10/09/2019 Learn CBSE/Class 12/Mathematics/Integrals/NCERT Solutions/Miscellaneous Exercise 7
Answered on 07/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Exercise 9.4
dy/dx =(2x^2+x)/(x^2+1)(x+1)=(ax+b)/(x^2+1) +c/(x+1)
compare 2x^2 +x=ax^2+ax+bx+b+cx^2 +c
x^2 term a+c=2,x terms a+b=1,constant b +c=0->c=-b
a-b=2 then a=b+2,b+2+b=1->2b=-1=b=-1/2 ,c=1/2
a=-1/2 +2=3/2
dy=(ax+b)/(x^2+1) +c/(x+1)=((3x/2)-(1/2)/(x^2+1) +1/2/(x+1) dx
apply integration both sides
y=3log(x^2+1)-1/4 tan^-1+ 1/2 log(x+1)
Answered on 04/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Exercise 4.6
Answered on 03/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Exercise 4.6
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
10
Board
CBSE, IGCSE, ISC/ICSE, State, International Baccalaureate
IB Subjects taught
Physics, Mathematics
ISC/ICSE Subjects taught
Mathematics, Computer Science
CBSE Subjects taught
Physics, Mathematics, Computer Science
IGCSE Subjects taught
Mathematics
Experience in School or College
Since 2008 to till date i am teaching for PUC(CBSE) board level ,IITJEE Mains ,NEET Physics .i brought 100% results in my 10 year teaching .
Taught in School or College
Yes
State Syllabus Subjects taught
Education, Physics, Computer Science, Electronics, Mathematics, French, Telugu
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
5
Engineering Entrance Exams
IIT JEE Coaching Classes
IITJEE Coaching
IIT JEE Mains Coaching, IIT JEE Crash Course
Type of class
Crash Course, Regular Classes
IIT-JEE Subjects
Maths
Answered on 10/09/2019 Learn CBSE/Class 12/Mathematics/Integrals/NCERT Solutions/Miscellaneous Exercise 7
Answered on 07/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Exercise 9.4
dy/dx =(2x^2+x)/(x^2+1)(x+1)=(ax+b)/(x^2+1) +c/(x+1)
compare 2x^2 +x=ax^2+ax+bx+b+cx^2 +c
x^2 term a+c=2,x terms a+b=1,constant b +c=0->c=-b
a-b=2 then a=b+2,b+2+b=1->2b=-1=b=-1/2 ,c=1/2
a=-1/2 +2=3/2
dy=(ax+b)/(x^2+1) +c/(x+1)=((3x/2)-(1/2)/(x^2+1) +1/2/(x+1) dx
apply integration both sides
y=3log(x^2+1)-1/4 tan^-1+ 1/2 log(x+1)
Answered on 04/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Exercise 4.6
Answered on 03/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Exercise 4.6
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