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Asked by Misha Last Modified
Answer Graph of 9x – 5y + 160 = 0
To graph the equation 9x – 5y + 160 = 0, we'll first rewrite it in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
Step 1: Rewrite the equation in slope-intercept form
9x – 5y + 160 = 0
Subtract 9x from both sides:
-5y = -9x - 160
Divide both sides by -5 to isolate y:
y = (9/5)x + 32
Now we have the equation in slope-intercept form.
Step 2: Identify the slope and y-intercept
The slope (m) is 9/5 and the y-intercept (b) is 32.
Step 3: Plot the y-intercept and use the slope to find additional points
Now, let's plot the y-intercept at (0, 32). From there, we'll use the slope to find another point. The slope of 9/5 means that for every 5 units we move to the right along the x-axis, we move 9 units upwards along the y-axis.
So, starting from (0, 32), if we move 5 units to the right, we move 9 units up to get the next point.
Step 4: Plot the points and draw the line
Plot the y-intercept at (0, 32) and the next point at (5, 41). Then, draw a line through these points to represent the graph of the equation.
Finding the value of y when x = 5
To find the value of y when x = 5, we'll substitute x = 5 into the equation and solve for y.
9x – 5y + 160 = 0
9(5) – 5y + 160 = 0
45 – 5y + 160 = 0
Combine like terms:
-5y + 205 = 0
Subtract 205 from both sides:
-5y = -205
Divide both sides by -5 to solve for y:
y = 41
So, when x = 5, y = 41.
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