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Asked by Pritam Last Modified
Answer Let y = mx + c be the line through point (–1, 2).
Accordingly, 2 = m (–1) + c.
⇒ 2 = –m + c
⇒ c = m + 2
∴ y = mx + m + 2 … (1)
The given line is
x + y = 4 … (2)
On solving equations (1) and (2), we obtain
is the point of intersection of lines (1) and (2).
Since this point is at a distance of 3 units from point (– 1, 2), according to distance formula,
Thus, the slope of the required line must be zero i.e., the line must be parallel to the x-axis.
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