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(b) n = 3, l = 0 Asked by Balendra Last Modified
Answer (a) Total number of electrons in an atom for a value of n = 2n2
∴ For n = 4,
Total number of electrons = 2 (4)2
= 32
The given element has a fully filled orbital as
1s2 2s2 2p6 3s2 3p6 4s2 3d10.
Hence, all the electrons are paired.
∴ Number of electrons (having n = 4 and ) = 16
(b) n = 3, l = 0 indicates that the electrons are present in the 3s orbital. Therefore, the number of electrons having n = 3 and l = 0 is 2.
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