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Asked by Himanshu Last Modified
Answer 
Apoorva Purohit
Let V be the speed of the bus running between towns A and B.
Speed of the cyclist, v = 20 km/h
Relative speed of the bus moving in the direction of the cyclist
= V – v = (V – 20) km/h
The bus went past the cyclist every 18 min i.e., 
(when he moves in the direction of the bus).
Distance covered by the bus = 
… (i)
Since one bus leaves after every T minutes, the distance travelled by the bus will be equal to 
Both equations (i) and (ii) are equal.
Relative speed of the bus moving in the opposite direction of the cyclist
= (V + 20) km/h
Time taken by the bus to go past the cyclist 
From equations (iii) and (iv), we get
Substituting the value of V in equation (iv), we get
(40+20)×660 = 40T60T = 36040T = 9 min
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