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Find the equations of all lines having slope 0 which are tangent to the curve .
The equation of the given curve is.
The slope of the tangent to the given curve at any point (x, y) is given by,
If the slope of the tangent is 0, then we have:
When x = 1,
∴The equation of the tangent throughis given by,
Hence, the equation of the required line is
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Concept- find dy/dx for the curve and equate it to 0.
you may face difficulty for finding derivative due to lack of practice.
Hint: Apply u/v formula for differentiation and make numerator zero so that slope equals to zero.
check after dy/dx numerator is -(2x-2).
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Find the slope of the normal to the curve x = 1 − a sin θ, y = b cos2θ at .
Find the slope of the tangent to the curve y = 3x4 − 4x at x = 4.
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