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Find the maximum profit that a company can make, if the profit function is given by

p(x) = 41 − 72x − 18x

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The profit function is given as p(x) = 41 − 72x − 18x2.∴ p'(x)=−72−36x ⇒x=−7236=−2 Also,p''(−2)=−36<0 By second derivative test, x=−2x=-2 is the point of local maxima of p. ∴ Maximum profit=p(−2)= 41−72(−2)−18(−2)2=41+144−72=113 Hence,...
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The profit function is given as p(x) = 41 − 72x − 18x2.
∴ p'(x)=7236x

x=7236=2

Also,
p''(2)=36<0

By second derivative test, x=2x=-2 is the point of local maxima of p.

∴ Maximum profit=p(2)= 4172(2)18(2)2=41+14472=113

Hence, the maximum profit that the company can make is 113 units.
The solution given in the book has some error. The solution is created according to the question given in the book.

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p' (x) = -72 -36x = 0 => x = - 2 p(- 2) = 113
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