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Asked by Jacob Last Modified
Answer 
Deepika Agrawal
"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."
Given, the actual path length travelled is 23 km, displacement is 10 km and the time taken is 28 min.
(a)
Average speed of the taxi is given as,
v avg = Total Path length Time
Here, s is the total path length
Substitute the values in above equation.
v avg = Total Path length Time = 23 km ( 28 min )( 1 h 60 min ) =49.3 km/h
Hence, the average speed of the taxi is 49.3 km/h .
(b)
Magnitude of the average velocity is given as,
v avg = Displacement Time
Substitute the values in the above equation.
v avg = Displacement Time = 10 km ( 28 min )( 1 h 60 min ) =21.4 km/h
(c)
From the calculation in (a) and (b), it is obtained that the average speed is not equal to the magnitude of average velocity.
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a) To find the avearage speed of the taxi,
Given data,
Total distance travelled: 23 km
Total time taken: 28 min, 28/60=0.4666hr
average speed = Total distance travelled / Total time taken
=23/0.4666
=49.29km/h
=50km/hr
b) Distance between the hotel and the station = 10 km = Displacement of the car
To find the magnitude of average velocity,
Average velocity =Displacement/ Total time taken
=10/0.4666
= 21.43km/h
hence, the average speed and average velocity are not equal.
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