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An elevator descends into a mine shaft at the rate of 5m/min. The descent starts from 50m above the ground level, How much time will it take to reach -150m ?

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Total distance=50-(-150)=50+150=200 M Time=distance ÷speed= 200÷5=40 min.
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PHYSICS for JEE/NEET,CBSE,NCERT,GUJARATI boards.Complete H C Verma Volume 1&2 with unsolved problems

time =(Distance has to travel/ speed) = ((50+150)/5 = 200/5 = 40 minutes
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20 mins for 50m above ground and 20 mins for 100 below ground. In total, it takes 30 mins.
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