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Asked by Y Last Modified
Answer It is given that:
KH = 1.67 × 108 Pa
_18-11-08)_Utpal_12_Chemistry_2_12_html_m1501b261.gif){kind=small}
= 2.5 atm = 2.5 × 1.01325 × 105 Pa
= 2.533125 × 105 Pa
According to Henry’s law:
_18-11-08)_Utpal_12_Chemistry_2_12_html_m1991adad.gif)
= 0.00152
We can write, _18-11-08)_Utpal_12_Chemistry_2_12_html_6081c2db.gif)
[Since, _18-11-08)_Utpal_12_Chemistry_2_12_html_12ffb063.gif){kind=small}
is negligible as compared to_18-11-08)_Utpal_12_Chemistry_2_12_html_4cb78f2d.gif){kind=small}
]
In 500 mL of soda water, the volume of water = 500 mL
[Neglecting the amount of soda present]
We can write:
500 mL of water = 500 g of water
_18-11-08)_Utpal_12_Chemistry_2_12_html_3a1cd9f4.gif){kind=small}
= 27.78 mol of water
Now, _18-11-08)_Utpal_12_Chemistry_2_12_html_m4f60632c.gif)
_18-11-08)_Utpal_12_Chemistry_2_12_html_21a24334.gif)
Hence, quantity of CO2 in 500 mL of soda water = (0.042 × 44)g
= 1.848 g
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