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Asked by Vruthi Last Modified
Answer Distance between the slits, d = 0.28 mm = 0.28 × 10−3 m
Distance between the slits and the screen, D = 1.4 m
Distance between the central fringe and the fourth (n = 4) fringe,
u = 1.2 cm = 1.2 × 10−2 m
In case of a constructive interference, we have the relation for the distance between the two fringes as:
Where,
n = Order of fringes = 4
λ = Wavelength of light used
∴
Hence, the wavelength of the light is 600 nm.
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