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Asked by Rakesh Last Modified
Answer 
Ram Mirdha
Chemistry Faculty Allen career institute , 5 year experience, trained more than 2500 students
2NaoH +2Al +2H2O --. 2NaAlO2 + 3H2
From the reaction
2 moles of Al produces 3 moles of H2
∴ 1mole of Al will produce 1.5 moles of H2
Moles of Al = weight of Al/ molecular weight of Al
= .15/27
Now moles of H2 = (3/2)×(.15/27)
= 1/120
Volume of 1 mole of any gas is 22.4 L
∴Volume of H2 = 22.4×(1/20)
= 0.1867 Litre
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