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Asked by Gaurang Last Modified
Answer 
Rahul S
Tutor
(i) Perimeter , P = 2(x+y)
(ii) A = x⋅ y
∴
When x = 8 cm and y = 6 cm, 
Hence, the area of the rectangle is increasing at the rate of 2 cm2/min.
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Harshit Bhardwaj
Since the length (x) is decreasing at the rate of 5 cm/minute and the width (y) is increasing at the rate of 4 cm/minute, we have:
and 
(a) The perimeter (P) of a rectangle is given by,
P = 2(x + y)
Hence, the perimeter is decreasing at the rate of 2 cm/min.
(b) The area (A) of a rectangle is given by,
A = x⋅ y
∴
When x = 8 cm and y = 6 cm,
Hence, the area of the rectangle is increasing at the rate of 2 cm2/min.
read less
Perimeter of rectangle =2(x+y) dp/dt= 2( dx/dt +dy/dt =2×(-5+4)=-2 area of rectangle =x×y dA/dt=xdy/dt+ ydx/dt=8×4+-5×6=2
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Related Questions
The rate of change of the area of a circle with respect to its radius r at r = 6 cm is
(A) 10π (B) 12π (C) 8π (D) 11π
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