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Where will the hand of a clock stop if it (a) starts at 12 and makes 1 / 2 of a revolution, clockwise?

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If the hour hand of a clock starts at 12 and makes 1/2 of a revolution clockwise, it will stop at the position that is exactly opposite its starting position. Since a full revolution of the hour hand covers 360 degrees, and it makes 1/2 of a revolution clockwise, it will cover 1/2×360∘=180∘ Therefore,...
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If the hour hand of a clock starts at 12 and makes 1/2 of a revolution clockwise, it will stop at the position that is exactly opposite its starting position.

Since a full revolution of the hour hand covers 360 degrees, and it makes 1/2 of a revolution clockwise, it will cover 1/2×360∘=180∘

Therefore, the hour hand will stop at the position exactly opposite to 12, which is 6 on the clock face.

 
 
 
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