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ABC is a right-angled triangle and O is the mid point of the side opposite to the right angle. Explain why O is equidistant from A, B and C. (The dotted lines are drawn additionally to help you).
Asked by Sona Last Modified
Answer Draw lines AD and DC such that AD||BC, AB||DC
AD = BC, AB = DC
ABCD is a rectangle as opposite sides are equal and parallel to each other and all the interior angles are of 90º.
In a rectangle, diagonals are of equal length and also these bisect each other.
Hence, AO = OC = BO = OD
Thus, O is equidistant from A, B, and C.
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