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A bus decreases its speed from 80 km h−1 to 60 km h−1 in 5 s. Find the acceleration of the bus?

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Initial speed of the bus, u = 80 km/h Final speed of the bus, v = 60 km/h Time take to decrease the speed, t = 5 s Here, the negative sign of acceleration indicates that the velocity of the car is decreasing.
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Initial speed of the bus, u = 80 km/h

Final speed of the bus, v = 60 km/h

Time take to decrease the speed, t = 5 s

Here, the negative sign of acceleration indicates that the velocity of the car is decreasing.

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B.tech in ECE as well as B.Ed & CTET qualified with 8+ years of experience in teaching of Physics

Concept- 1 km/hr = 1000/(60x60)m/s =( 5/18 )m/s ( Always convert all quantities into same unit) (prefer SI Units) Given- u = 80km/hr = (80x 5)/18 m/s, v= 60km/hr=( 60x 5) /18 m/s, t= 5 sec Solution- since V=u+at ∴ a= (v-u) /t = ÷ 5 Take 5/18 common =(5/18) ÷5 Numerator...
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Concept- 1 km/hr = 1000/(60x60)m/s

=( 5/18 )m/s ( Always convert all quantities into same unit) (prefer SI Units) 

Given- u = 80km/hr = (80x 5)/18 m/s, 

v= 60km/hr=( 60x 5) /18 m/s, 

t= 5 sec

Solution- since V=u+at

∴ a= (v-u) /t

= [{( 60x5)18}-{(80x5) /18}]÷ 5

Take 5/18 common

=(5/18) [60-80]÷5

Numerator and denominator 5 will be cancelled out and you will get

= -20/18 = (-10/9) m/s²

Here minus sign indicates that acceleration is negative I. e it is Retardation or Velocity is decreasing with time

 

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Completed graduation in Mathematics from Calcutta University

(10/9) m/s^2
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a = V-U/T so ..1st we will change the speed in m/sec by multiplying it with 5/18 80*5/18=200/9,,,60*5/18=150/9 a = 150/9-200/9and then divide it by 5 i.e a= -50/9*5=-10/9m/sec answer
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