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Asked by Alifiya Last Modified
Answer 
Tasneem
The steps mentioned below will be followed to construct the required triangle.
Step I: Draw a line segment AB of 11 cm.
(As XY + YZ + ZX = 11 cm)
Step II: Construct an angle, ∠PAB, of 30° at point A and an angle, ∠QBA, of 90° at point B.
Step III: Bisect ∠PAB and ∠QBA. Let these bisectors intersect each other at point X.
Step IV: Draw perpendicular bisector ST of AX and UV of BX.
Step V: Let ST intersect AB at Y and UV intersect AB at Z.
Join XY, XZ.
ΔXYZ is the required triangle.
PAB of 30o at point A and an angle QBA of 90o at point B.PAB and QBA. Let these bisectors intersect each other at point X.
XYZ is the required triangle.
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