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why 0/0 is a indeterminate form ?

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Division by zero is an operation for which you cannot find an answer, so it is disallowed. You can understand why if you think about how division and multiplication are related. 10 divided by 5 is 2 because 5 times 2 is 10 10 divided by 0 is x would mean that 0 times x = 10 But...
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Division by zero is an operation for which you cannot find an answer, so it is disallowed. You can understand why if you think about how division and multiplication are related. 10 divided by 5 is 2 because 5 times 2 is 10 10 divided by 0 is x would mean that 0 times x = 10 But no value would work for x because 0 times any number is 0. So division by zero doesn't work. Actually , An indeterminate form does not mean that the limit is non-existent or cannot be determined, but rather that the properties of its limits are not valid. In higher class you will get to know how to solve indeterminate form there are 7 indeterminate form(Chapter:Limit) read less
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0/0 takes values based on the context and thus is indeterminate in general. It is not undefined. It has definition like in limits. This means one can't associate a value with it in one context and use the same value in another context. Thus it is indeterminate. E.g:- value of 2/3 is always the same...
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0/0 takes values based on the context and thus is indeterminate in general. It is not undefined. It has definition like in limits. This means one can't associate a value with it in one context and use the same value in another context. Thus it is indeterminate. E.g:- value of 2/3 is always the same in all contexts. That is not the case with 0/0. read less
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"Read , Recall and Procure"

The most common example of an indeterminate form occurs as the ratio of two functions, in which both of these functions tend to zero in the limit, and is referred to as "the indeterminate form 0/0". -
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Math Stats AI Data Science ML Big Data Python Educator

In the case of 0/0 we typically think of a fraction that has a numerator of zero as being zero.
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B.Tech, Spoken English, EEC, MATLAB, CET Coaching Tutor with 20 years of experience

The most common example of an indeterminate form occurs as the ratio of two functions, in which both of these functions tend to zero in the limit, and is referred to as "the indeterminate form 0/0". As x approaches 0, the ratios x/x3, x/x, and x2/x go to ?, 1, and 0 respectively.
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Computer Expert

Let 0/0=k Or (0/0) 0 =k*0 Or 0=k*0 Here k can be any number we can't define it. Therefore k =0/0 is indeterminate form.
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Teaching is my passion!!!!

bcse there is no specific limit to calculate such form
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Guitarist, geek and teacher

The 0/0 fraction is indeterminate and is not dealt with except at the calculus level. Any number divided by 0 tends to infinity and is thus unsolvable. Example tan(90) = 1/0 (indeterminate form.
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Teacher

From calculus point of view there is no specific limit for such form so it is undefined.
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English teacher with 5 years of experience in teaching,• Instructed students in English language arts, including writing, reading comprehension, speaking, listening and understanding

The most common example of an indeterminate form occurs as the ratio of two functions, in which both of these functions tend to zero in the limit, and is referred to as "the indeterminate form 0/0". As x approaches 0, the ratios x/x3, x/x, and x2/x go to ?, 1, and 0 respectively. In each case, if the...
read more
The most common example of an indeterminate form occurs as the ratio of two functions, in which both of these functions tend to zero in the limit, and is referred to as "the indeterminate form 0/0". As x approaches 0, the ratios x/x3, x/x, and x2/x go to ?, 1, and 0 respectively. In each case, if the limits of the numerator and denominator are substituted, the resulting expression is 0/0, which is undefined. So, in a manner of speaking, 0/0 can take on the values 0, 1 or ?, and it is possible to construct similar examples for which the limit is any particular value. More formally, the fact that the functions f(x) and g(x) both approach 0 as x approaches some limit point c is not enough information to evaluate the limit \lim_{x \to c} \frac{f(x)}{g(x)}. \! read less
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