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Class 12 Tuition > Learn Class XI-XII Tuition (PUC) > 5 × 1016 electrons pass across the section of a conductor...
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5 × 1016 electrons pass across the section of a conductor in 1 minutes and 20 seconds. The current is flowing a.) 0.1 mA. b.) 1 mA. c.) 10 mA. d.) 100 mA.

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Answer - (A) Electric Current ( I ) = Quantity of Charge (Q) time (t) Charge Q = ne (no. of electrons electrons × charge on electron ) Charge on electron = 1.6 × 10-19 C here n = 5 ×1016 t = 1min...
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Answer - (A)

Electric Current ( I ) = Quantity of Charge (Q)  

                                          time (t)

Charge Q = ne    (no. of electrons electrons × charge on electron )

                Charge on electron = 1.6 × 10-19 C

                       here n = 5 ×1016      t = 1min 20sec = 80 sec

                   I =  ne   = 5 ×1016 × 1.6 × 10-19   = 1016 × 10-19  = 10-4 A = 103 mA = 10-1mA = 0.1mA

                          t                     80                              10                             104       ( 1A = 103mA )

                    

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Charge of an electron is 1.6X10^19 Number of electron is 5X10^16 time=1minute 20sec=60sec 20sec=80sec current=(number of electron x each electron value)/time current=((5x10^16)x(1.6x10^-19))/80sec current=(8x10^-3)/80 current=0.1mili amps
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Don't want to over express myself, just join and feel the experience.

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Professional Chemistry Teacher for IIT JEE/NEET UG,Online expert for IB/IGCSE/AP CURRICULUM

Q=n.e, q=c.t, ne=ct, 5x10*16x1.6x10*-19=cx80, c=5x10*16x1.6x10*-19/80Amps=5x10*16x1.6x10*-19/80x10*3milli amps
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Mathematics

none of them is correct. correct answer is 1.01x 10to power -19 ampere.
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