Badripur, Dehradun, India - 248005.
4
Details verified of Ashutosh Rawat✕
Identity
Education
Know how UrbanPro verifies Tutor details
Identity is verified based on matching the details uploaded by the Tutor with government databases.
Hindi Mother Tongue (Native)
English Basic
Uttaranchal University 2021
Bachelor of Science (B.Sc.)
Doon University 2023
Master of Science (M.Sc.)
S.G.R.R. Public School, Vashant Vihar 2018
12th
Badripur, Dehradun, India - 248005
ID Verified
Phone Verified
Email Verified
Facebook Verified
Report this Profile
Is this listing inaccurate or duplicate? Any other problem?
Please tell us about the problem and we will fix it.
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
CBSE
Preferred class strength
Group Classes, One on one/ Private Tutions
CBSE Subjects taught
Applied Mathematics, Mathematics
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
3
Board
CBSE
Preferred class strength
Group Classes, One on one/ Private Tutions
CBSE Subjects taught
Applied Mathematics, Mathematics
Taught in School or College
No
1 out of 5 1 review
Shivanshu Kumar
BSc Tuition
I didn't like
Teaching Method
Reply by Ashutosh
I think there is a misunderstanding as we haven't done any demo sessions with you. Still, if you have any queries or doubts feel free to reach us.
1. Which school boards of Class 12 do you teach for?
CBSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 3 years.
Answered on 04/08/2023 Learn Tuition
Answered on 21/06/2020 Learn CBSE/Class 11
∫logxdx=∫1.logxdx
In this condition we will use integration by parts .
⇒ ∫logxdx = logx ∫1dx - ∫{d/dx(logx)∫1dx}dx
=logx . x - ∫{(1/x ).(x)}dx
=x logx - x + C
Answered on 12/06/2020 Learn Tuition
Answered on 03/09/2018 Learn Tuition/Class XI-XII Tuition (PUC)
Answered on 03/09/2018 Learn Tuition/Class XI-XII Tuition (PUC)
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
CBSE
Preferred class strength
Group Classes, One on one/ Private Tutions
CBSE Subjects taught
Applied Mathematics, Mathematics
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
3
Board
CBSE
Preferred class strength
Group Classes, One on one/ Private Tutions
CBSE Subjects taught
Applied Mathematics, Mathematics
Taught in School or College
No
1 out of 5 1 review
Shivanshu Kumar
BSc Tuition
I didn't like
Teaching Method
Reply by Ashutosh
I think there is a misunderstanding as we haven't done any demo sessions with you. Still, if you have any queries or doubts feel free to reach us.
Answered on 04/08/2023 Learn Tuition
Answered on 21/06/2020 Learn CBSE/Class 11
∫logxdx=∫1.logxdx
In this condition we will use integration by parts .
⇒ ∫logxdx = logx ∫1dx - ∫{d/dx(logx)∫1dx}dx
=logx . x - ∫{(1/x ).(x)}dx
=x logx - x + C
Answered on 12/06/2020 Learn Tuition
Answered on 03/09/2018 Learn Tuition/Class XI-XII Tuition (PUC)
Answered on 03/09/2018 Learn Tuition/Class XI-XII Tuition (PUC)
Share this Profile
Reply to 's review
Enter your reply*
Your reply has been successfully submitted.
Certified
The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.