Kalyan Vihar Rajpura, Delhi, India - 110007.
Details verified of Harsh Sharma✕
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English
Hindi
University of Delhi Pursuing
Bachelor of Science (B.Sc.)
178/1, Rajpura, Kalyan Vihar
Kalyan Vihar Rajpura, Delhi, India - 110007
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Physics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Physics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics, Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics, Science
Taught in School or College
No
1. Which school boards of Class 12 do you teach for?
CBSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition and Class 9 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for less than a year.
Answered on 29/10/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.2
We know that the expression for the velocity is,
Substitute the values given in the question to find the distance of the space ship from the ground station.
First convert the time from minutes to seconds using the fact that there are 60 seconds in one minute.
We have,
time=5×60 s
=300 s
v=3×10^8 m/s
So, the distance is
d= v×t
d=9×10^10 m
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Physics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Physics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Science, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics, Science
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics, Science
Taught in School or College
No
Answered on 29/10/2019 Learn CBSE/Class 9/Science/Unit 3-Motion, Force and Work/Motion/NCERT Solutions/Intext Exercise 8.2
We know that the expression for the velocity is,
Substitute the values given in the question to find the distance of the space ship from the ground station.
First convert the time from minutes to seconds using the fact that there are 60 seconds in one minute.
We have,
time=5×60 s
=300 s
v=3×10^8 m/s
So, the distance is
d= v×t
d=9×10^10 m
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