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Mayank Verma Class 11 Tuition trainer in Delhi

Mayank Verma

Andrews Ganj, Delhi, India - 110049.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Mayank Verma conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Mayank is located in Andrews Ganj, Delhi. Mayank takes Online Classes- via online medium. He has 2 years of teaching experience . Mayank has completed Bachelor of Technology (B.Tech.) from GGSIPU in 2016. HeĀ is well versed in Hindi and English.

Languages Spoken

Hindi

English

Education

GGSIPU 2016

Bachelor of Technology (B.Tech.)

Address

Andrews Ganj, Delhi, India - 110049

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Email Verified

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE

CBSE Subjects taught

Physics, Chemistry

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

2

Board

CBSE

CBSE Subjects taught

Physics, Chemistry

Taught in School or College

No

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

CBSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition, Class I-V Tuition and Online Tuition Classes Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Mayank Verma (2)

Answered on 05/06/2017 Learn CBSE/Class 12/English +1 Tuition/Class XI-XII Tuition (PUC)

Don't try to learn any language by translating word to word from the language you know. It means don't learn English by translating the words from Hindi.
Answers 73 Comments
Dislike Bookmark

Answered on 05/06/2017 Learn Tuition/Class IX-X Tuition

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. This verbal... ...more
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. This verbal statement can be expressed in equation form as follows: a = Fnet / m The above equation is often rearranged to a more familiar form as shown below. The net force is equated to the product of the mass times the acceleration. Fnet = m x a Consistent with the above equation, a unit of force is equal to a unit of mass times a unit of acceleration. By substituting standard metric units for force, mass, and acceleration into the above equation, the following unit equivalency can be written. 1 Newton = 1 kg x m/s2 The definition of the standard metric unit of force is stated by the above equation. One Newton is defined as the amount of force required to give a 1-kg mass an acceleration of 1 m/s/s.
Answers 183 Comments
Dislike Bookmark

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE

CBSE Subjects taught

Physics, Chemistry

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

2

Board

CBSE

CBSE Subjects taught

Physics, Chemistry

Taught in School or College

No

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

No Reviews yet!

Answers by Mayank Verma (2)

Answered on 05/06/2017 Learn CBSE/Class 12/English +1 Tuition/Class XI-XII Tuition (PUC)

Don't try to learn any language by translating word to word from the language you know. It means don't learn English by translating the words from Hindi.
Answers 73 Comments
Dislike Bookmark

Answered on 05/06/2017 Learn Tuition/Class IX-X Tuition

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. This verbal... ...more
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. This verbal statement can be expressed in equation form as follows: a = Fnet / m The above equation is often rearranged to a more familiar form as shown below. The net force is equated to the product of the mass times the acceleration. Fnet = m x a Consistent with the above equation, a unit of force is equal to a unit of mass times a unit of acceleration. By substituting standard metric units for force, mass, and acceleration into the above equation, the following unit equivalency can be written. 1 Newton = 1 kg x m/s2 The definition of the standard metric unit of force is stated by the above equation. One Newton is defined as the amount of force required to give a 1-kg mass an acceleration of 1 m/s/s.
Answers 183 Comments
Dislike Bookmark

Mayank Verma conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Mayank is located in Andrews Ganj, Delhi. Mayank takes Online Classes- via online medium. He has 2 years of teaching experience . Mayank has completed Bachelor of Technology (B.Tech.) from GGSIPU in 2016. HeĀ is well versed in Hindi and English.

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