Sainik Farm Saiyad ul Ajaib, Delhi, India - 110030.
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Hindi Mother Tongue (Native)
English Mother Tongue (Native)
U.p.t.u 2015
Bachelor of Technology (B.Tech.)
Sainik Farm Saiyad ul Ajaib, Delhi, India - 110030
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
ISC/ICSE, CBSE
ISC/ICSE Subjects taught
Geography, Mathematics, History, EVS
CBSE Subjects taught
Mathematics, History, Geography
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, CBSE
CBSE Subjects taught
Social science
ICSE Subjects taught
History and Civics, EVS, Geography
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
1
Fees
₹ 250.0 per hour
Board
ICSE, CBSE
CBSE Subjects taught
Science, Mathematics, EVS, Social Science
ICSE Subjects taught
Social Studies, Science, EVS, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, CBSE
CBSE Subjects taught
Mathematics, Social science, Science
ICSE Subjects taught
Physics, English, Biology, History and Civics, Mathematics, EVS, Chemistry, Geography
Taught in School or College
No
1. Which school boards of Class 12 do you teach for?
ISC/ICSE and CBSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 12 Tuition, Class 9 Tuition and Class I-V Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 09/11/2019 Learn CBSE/Class 12/Science/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
Capacitance of the capacitor, C = 600 pF Potential difference, V = 200 V Electrostatic energy stored in the capacitor is given by, If supply is disconnected from the capacitor and another capacitor of capacitance C = 600 pF is connected to it, then equivalent capacitance (C') of the combination is given by, New electrostatic energy can be calculated as Loss in electrostatic enegy = E - E' = 1.2 x 10-5 - 0.6 x 10-5 = 0.6 x 10-5 = 6 x 10-6 J Therefore, the electrostatic energy lost in the process is 6 x 10-6 J.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
ISC/ICSE, CBSE
ISC/ICSE Subjects taught
Geography, Mathematics, History, EVS
CBSE Subjects taught
Mathematics, History, Geography
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, CBSE
CBSE Subjects taught
Social science
ICSE Subjects taught
History and Civics, EVS, Geography
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
1
Fees
₹ 250.0 per hour
Board
ICSE, CBSE
CBSE Subjects taught
Science, Mathematics, EVS, Social Science
ICSE Subjects taught
Social Studies, Science, EVS, Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ICSE, CBSE
CBSE Subjects taught
Mathematics, Social science, Science
ICSE Subjects taught
Physics, English, Biology, History and Civics, Mathematics, EVS, Chemistry, Geography
Taught in School or College
No
Answered on 09/11/2019 Learn CBSE/Class 12/Science/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
Capacitance of the capacitor, C = 600 pF Potential difference, V = 200 V Electrostatic energy stored in the capacitor is given by, If supply is disconnected from the capacitor and another capacitor of capacitance C = 600 pF is connected to it, then equivalent capacitance (C') of the combination is given by, New electrostatic energy can be calculated as Loss in electrostatic enegy = E - E' = 1.2 x 10-5 - 0.6 x 10-5 = 0.6 x 10-5 = 6 x 10-6 J Therefore, the electrostatic energy lost in the process is 6 x 10-6 J.
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