Bara Putki, Dhanbad, India - 828116.
1
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Hindi Basic
Dav public school Pursuing
12
Bara Putki, Dhanbad, India - 828116
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Handwriting classes
1
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
1
Board
CBSE
CBSE Subjects taught
English, Hindi
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
1. Which classes do you teach?
I teach Class I-V Tuition, Handwriting and Hindi Language Classes.
2. Do you provide a demo class?
No, I don't provide a demo class.
3. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 22/05/2020 Learn Tuition
5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx
Rearranging the terms: =>
2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz) +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0
Now, LHS has all the terms non negative as all the terms are square of some number But RHS is zero.
So, all the non negative cannot add up to 0, hence all the numbers on the LHS has to be zero so that the RHS becomes 0. ∴ x-y = 0 , y-z =0, z-x=0 => x=y=z ∴
x:y:z =1:1:1
Answered on 22/05/2020 Learn Tuition
Answered on 22/05/2020 Learn Tuition
Answered on 22/05/2020 Learn Hobby/Handwriting
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Handwriting classes
1
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
1
Board
CBSE
CBSE Subjects taught
English, Hindi
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Answered on 22/05/2020 Learn Tuition
5x^2 + 5y^2 + 5z^2 = 4xy+4yx+4zx
Rearranging the terms: =>
2(x^2+y^2 -2xy) + 2(y^2+z^2 - 2yz) +2(z^2+x^2 -2zx) + x^2+y^2 +z^2 = 0 => 2(x-y)^2 + 2(y-z)^2 + 2(z-x)^2 + x^2 + y^2 + z^2 = 0
Now, LHS has all the terms non negative as all the terms are square of some number But RHS is zero.
So, all the non negative cannot add up to 0, hence all the numbers on the LHS has to be zero so that the RHS becomes 0. ∴ x-y = 0 , y-z =0, z-x=0 => x=y=z ∴
x:y:z =1:1:1
Answered on 22/05/2020 Learn Tuition
Answered on 22/05/2020 Learn Tuition
Answered on 22/05/2020 Learn Hobby/Handwriting
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