City Centre, Durgapur, India - 713216.
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Bengali Proficient
Hindi Proficient
English Proficient
west Bengal state council of technical education 2007
electronics and communication engineering
City Centre, Durgapur, India - 713216
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3 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
7
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Physics
CBSE Subjects taught
Physics
Taught in School or College
Yes
State Syllabus Subjects taught
Physics
Teaching Experience in detail in Class 11 Tuition
Learn by easy Concept.
3 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
7
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Physics
CBSE Subjects taught
Physics
Taught in School or College
Yes
State Syllabus Subjects taught
Physics
Teaching Experience in detail in Class 12 Tuition
Learn by easy Concept.
3 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
7
Board
ICSE, CBSE
CBSE Subjects taught
Science
ICSE Subjects taught
Chemistry, Biology, Physics
Taught in School or College
Yes
Teaching Experience in detail in Class 9 Tuition
Learn with the easy concept.
3 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
7
Board
ICSE, CBSE
CBSE Subjects taught
Science
ICSE Subjects taught
Chemistry, Biology, Physics
Taught in School or College
Yes
Teaching Experience in detail in Class 10 Tuition
Learn with the easy concept.
5 out of 5 5 reviews
Sanjoy
"Very good teacher. Unlike and exceptional from all other teachers in durgapur. Teachs very easily. Very student friendly.covers each and every topic of the chapter. I have got compartment in PHYSICS and after studying ONE month, I got 90%in Physics. He is very experienced teacher.He is only one teacher in durgapur who doesn't teach students for money but as passion.He is dedicated to teaching. "
Deb Mondal
"Unique type of teacher, very Frank and interesting. He explains get well and also by showing inter actual and interested videos. He has a very much big sack of knowledge. I expect from all to take tuition from him only. "
Shresth Raj
"Excellent teacher with lots of experience. Teaches with easy made notes . Teaching style is unique which can help a simple child to learn and understand the concept. He also teaches with interactive videos which makes learning more easy ,simple , interesting and conceptual. "
Sahil Sinha
"His teaching style is awesome. He helped me a lot for preparing my boards. If you guys are searching for any good physics teacher than contact him. "
1. Which school boards of Class 12 do you teach for?
ISC/ICSE, CBSE, State
2. Have you ever taught in any School or College?
Yes
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition and Class 9 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 7 years.
Amoeba is a holozoic and protozoan. The digestion is intracellular as it is a unicellular organism. The food taken remains in a food vacuole or gastric vacuole formed by the cell membrane and a bit of...
1. Echo is a single reflection of a sound wave off a surface. Reverberation is the sound or the pattern created by the superposition of such echoes. 2. An echo can be heard only when the distance between...
a. Cornea: The cornea is the outermost layer of the eye and is primarily responsible for focusing the light that comes into our eyes. The cornea provides 66% of the optic power that the overall eye has....
Answered on 19/04/2018 Learn CBSE/Class 9/Science
For obtaining maximum height, here we can use the formula v2 - u2 = 2as
Where, v is the final velocity which will be zero as at the maximum height there will be no velocity. The value of 'a' will be (-g), u= initial velocity and s will give the maximum height reached by the object.
-u2 = -2gs or u2 = 2gs or s = u2/2g
Here in the above formula we can see the maximum height reached by the object is independent of the mass. Its only dependent on the initial velocity; u and gravity; g which is constant
So any two objects thrown with same velocity will reach same distance
Answered on 19/04/2018 Learn CBSE/Class 9/Science
Answered on 18/03/2018 Learn CBSE/Class 11/Science/Physics
3 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
7
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Physics
CBSE Subjects taught
Physics
Taught in School or College
Yes
State Syllabus Subjects taught
Physics
Teaching Experience in detail in Class 11 Tuition
Learn by easy Concept.
3 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
7
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Physics
CBSE Subjects taught
Physics
Taught in School or College
Yes
State Syllabus Subjects taught
Physics
Teaching Experience in detail in Class 12 Tuition
Learn by easy Concept.
3 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
7
Board
ICSE, CBSE
CBSE Subjects taught
Science
ICSE Subjects taught
Chemistry, Biology, Physics
Taught in School or College
Yes
Teaching Experience in detail in Class 9 Tuition
Learn with the easy concept.
3 Students Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
7
Board
ICSE, CBSE
CBSE Subjects taught
Science
ICSE Subjects taught
Chemistry, Biology, Physics
Taught in School or College
Yes
Teaching Experience in detail in Class 10 Tuition
Learn with the easy concept.
Answered on 19/04/2018 Learn CBSE/Class 9/Science
For obtaining maximum height, here we can use the formula v2 - u2 = 2as
Where, v is the final velocity which will be zero as at the maximum height there will be no velocity. The value of 'a' will be (-g), u= initial velocity and s will give the maximum height reached by the object.
-u2 = -2gs or u2 = 2gs or s = u2/2g
Here in the above formula we can see the maximum height reached by the object is independent of the mass. Its only dependent on the initial velocity; u and gravity; g which is constant
So any two objects thrown with same velocity will reach same distance
Answered on 19/04/2018 Learn CBSE/Class 9/Science
Answered on 18/03/2018 Learn CBSE/Class 11/Science/Physics
Amoeba is a holozoic and protozoan. The digestion is intracellular as it is a unicellular organism. The food taken remains in a food vacuole or gastric vacuole formed by the cell membrane and a bit of...
1. Echo is a single reflection of a sound wave off a surface. Reverberation is the sound or the pattern created by the superposition of such echoes. 2. An echo can be heard only when the distance between...
a. Cornea: The cornea is the outermost layer of the eye and is primarily responsible for focusing the light that comes into our eyes. The cornea provides 66% of the optic power that the overall eye has....
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City Centre, Durgapur 
