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Sree Sujana Class 11 Tuition trainer in Hoskote/>

Sree Sujana

Hoskote, Hoskote, India - 562114.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Education

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Overview

I am a teacher. I am giving online tuition, since i am certified Masters in Mathematics, Bachelor in Education
Key Skills:
- Good experience in teaching methods.
- Techniques to teach a particular lesson
- Contribution to any special event for the class/entire school.
- Very good exposure to Online Teaching.

. Experience: Having 5.5 years of experience in teaching field as a teacher in Mathematics and Physical Sciences subjects for 6th -12th standards

Languages Spoken

Telugu Mother Tongue (Native)

English Proficient

Education

Sri Krishnadevaraya University 2008

Master of Science (M.Sc.)

Address

Hoskote, Hoskote, India - 562114

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

State, CBSE

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

5

Board

CBSE, State, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Physics, Mathematics, Chemistry

Experience in School or College

• Oct 2014-2017: Working as a teacher in New Horizon School, Hoskote. • August 2009 – Feb 2011: worked as an online tutor in Tutorvista for 6th to 12th standards in Mathematics.

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

6

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Chemistry, Physics, Mathematics

Experience in School or College

• Oct 2014-2017: Working as a teacher in New Horizon School, Hoskote. • August 2009 – Feb 2011: worked as an online tutor in Tutorvista for 6th to 12th standards in Mathematics.

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics, EVS

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

6

Board

CBSE, State

CBSE Subjects taught

Mathematics

Experience in School or College

• Oct 2014-2017: Working as a teacher in New Horizon School, Hoskote. • August 2009 – Feb 2011: worked as an online tutor in Tutorvista for 6th to 12th standards in Mathematics.

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

State and CBSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 8 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 5 years.

Contact

Answers by Sree Sujana (4)

Answered on 26/06/2019 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Is polynomial y4 + 4y2 + 5 have zeroes or not?

Given, f(x) = x4 + 4x2 + 5 = (x2)2 + 4x2 + 5 Put x2 = a Hence x4 + 4x2 + 5 = (x2)2 + 4x2 + 5 = a2 + 4a + 5 To find the zero of the above polynomial, we take a2 + 4a + 5 = 0 The above equation does not have a real root Hence there is no zero for this given... ...more

Given, f(x) = x4 + 4x2 + 5

                 = (x2)2 + 4x2 + 5

Put x2 = a

Hence x4 + 4x2 + 5 = (x2)2 + 4x2 + 5

                              = a2 + 4a + 5

To find the zero of the above polynomial, we take a2 + 4a + 5 = 0

The above equation does not have a real root

Hence there is no zero for this given polynomial.

Answers 13 Comments
Dislike Bookmark

Answered on 26/06/2019 Learn Tuition

if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3

RHS= (x+y+z)(x2+y2+z2-xy-yz-zx) =x(x2+y2+z2-xy-yz-xz)+y(x2+y2+z2-xy-yz-zx)+z(x2+y2+z2-xy-yz-zx) =x3+xy2+xz2-x2y-xyz+x2y+y3+z2y-y2x-y2z-xyz+x2z+y2z+z3-xyz-yz2-z2x =x3+y3+z3+(x2y-x2y)+(y2z-y2z)+(y2z-y2z)-3xyz =x3+y3+z3-3xyz =LHS Hence proved. ...more

RHS= (x+y+z)(x2+y2+z2-xy-yz-zx)

       =x(x2+y2+z2-xy-yz-xz)+y(x2+y2+z2-xy-yz-zx)+z(x2+y2+z2-xy-yz-zx)

       =x3+xy2+xz2-x2y-xyz+x2y+y3+z2y-y2x-y2z-xyz+x2z+y2z+z3-xyz-yz2-z2x

        =x3+y3+z3+(x2y-x2y)+(y2z-y2z)+(y2z-y2z)-3xyz

        =x3+y3+z3-3xyz

        =LHS

Hence proved.

Answers 278 Comments
Dislike Bookmark

Answered on 26/06/2019 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Is polynomial y4 + 4y2 + 5 have zeroes or not?

...more

Answers 13 Comments
Dislike Bookmark

Answered on 18/06/2019 Learn Tuition

What are the fees for 9 class student Mathematics, Science and English?

Online tutions for maths 200/- per hour 3 class per week.
Answers 986 Comments
Dislike Bookmark

Contact

Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

State, CBSE

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

State, CBSE

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

5

Board

CBSE, State, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Physics, Mathematics, Chemistry

Experience in School or College

• Oct 2014-2017: Working as a teacher in New Horizon School, Hoskote. • August 2009 – Feb 2011: worked as an online tutor in Tutorvista for 6th to 12th standards in Mathematics.

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

6

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Chemistry, Physics, Mathematics

Experience in School or College

• Oct 2014-2017: Working as a teacher in New Horizon School, Hoskote. • August 2009 – Feb 2011: worked as an online tutor in Tutorvista for 6th to 12th standards in Mathematics.

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics, EVS

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

6

Board

CBSE, State

CBSE Subjects taught

Mathematics

Experience in School or College

• Oct 2014-2017: Working as a teacher in New Horizon School, Hoskote. • August 2009 – Feb 2011: worked as an online tutor in Tutorvista for 6th to 12th standards in Mathematics.

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

No Reviews yet!

Answers by Sree Sujana (4)

Answered on 26/06/2019 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Is polynomial y4 + 4y2 + 5 have zeroes or not?

Given, f(x) = x4 + 4x2 + 5 = (x2)2 + 4x2 + 5 Put x2 = a Hence x4 + 4x2 + 5 = (x2)2 + 4x2 + 5 = a2 + 4a + 5 To find the zero of the above polynomial, we take a2 + 4a + 5 = 0 The above equation does not have a real root Hence there is no zero for this given... ...more

Given, f(x) = x4 + 4x2 + 5

                 = (x2)2 + 4x2 + 5

Put x2 = a

Hence x4 + 4x2 + 5 = (x2)2 + 4x2 + 5

                              = a2 + 4a + 5

To find the zero of the above polynomial, we take a2 + 4a + 5 = 0

The above equation does not have a real root

Hence there is no zero for this given polynomial.

Answers 13 Comments
Dislike Bookmark

Answered on 26/06/2019 Learn Tuition

if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3

RHS= (x+y+z)(x2+y2+z2-xy-yz-zx) =x(x2+y2+z2-xy-yz-xz)+y(x2+y2+z2-xy-yz-zx)+z(x2+y2+z2-xy-yz-zx) =x3+xy2+xz2-x2y-xyz+x2y+y3+z2y-y2x-y2z-xyz+x2z+y2z+z3-xyz-yz2-z2x =x3+y3+z3+(x2y-x2y)+(y2z-y2z)+(y2z-y2z)-3xyz =x3+y3+z3-3xyz =LHS Hence proved. ...more

RHS= (x+y+z)(x2+y2+z2-xy-yz-zx)

       =x(x2+y2+z2-xy-yz-xz)+y(x2+y2+z2-xy-yz-zx)+z(x2+y2+z2-xy-yz-zx)

       =x3+xy2+xz2-x2y-xyz+x2y+y3+z2y-y2x-y2z-xyz+x2z+y2z+z3-xyz-yz2-z2x

        =x3+y3+z3+(x2y-x2y)+(y2z-y2z)+(y2z-y2z)-3xyz

        =x3+y3+z3-3xyz

        =LHS

Hence proved.

Answers 278 Comments
Dislike Bookmark

Answered on 26/06/2019 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Is polynomial y4 + 4y2 + 5 have zeroes or not?

...more

Answers 13 Comments
Dislike Bookmark

Answered on 18/06/2019 Learn Tuition

What are the fees for 9 class student Mathematics, Science and English?

Online tutions for maths 200/- per hour 3 class per week.
Answers 986 Comments
Dislike Bookmark

Contact

Sree Sujana conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Sree Sujana is located in Hoskote, Hoskote. Sree Sujana takes Online Classes- via online medium. She has 6 years of teaching experience . Sree Sujana has completed Master of Science (M.Sc.) from Sri Krishnadevaraya University in 2008. She is well versed in English and Telugu.

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