Dilsukhnagar, Hyderabad, India - 500059.
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Hindi Mother Tongue (Native)
English Proficient
Pondicherry University Pursuing
Bachelor of Science (B.Sc.)
Dilsukhnagar, Hyderabad, India - 500059
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
English, Science, Hindi, Social science, Mathematics
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
English, Science, Hindi, Social science, Mathematics
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
3
Board
IGCSE, State, ICSE, CBSE, International Baccalaureate
IB Subjects taught
Computers, Hindi, Physical Education, English, Science, Mathematics, French
CBSE Subjects taught
Computers, French, EVS, Mathematics, Hindi, English, Social Science, Science
ICSE Subjects taught
Mathematics, English, EVS, Hindi, Computer Science, Geography, Physics, Chemistry, French, History
IGCSE Subjects taught
Hindi, French, English, Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
French, Social science, Hindi, Mathematics, EVS, English, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
3
Board
IGCSE, State, ICSE, CBSE, International Baccalaureate
IB Subjects taught
Computers, Hindi, Physical Education, English, Science, Mathematics, French
CBSE Subjects taught
Computers, French, EVS, Mathematics, Hindi, English, Social Science, Science
ICSE Subjects taught
Mathematics, English, EVS, Hindi, Computer Science, Geography, Physics, Chemistry, French, History
IGCSE Subjects taught
Hindi, French, English, Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
French, Social science, Hindi, Mathematics, EVS, English, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
3
Board
IGCSE, State, ICSE, CBSE, International Baccalaureate
IB Subjects taught
Computers, Hindi, Physical Education, English, Science, Mathematics, French
CBSE Subjects taught
Computers, French, EVS, Mathematics, Hindi, English, Social Science, Science
ICSE Subjects taught
Mathematics, English, EVS, Hindi, Computer Science, Geography, Physics, Chemistry, French, History
IGCSE Subjects taught
Hindi, French, English, Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
French, Social science, Hindi, Mathematics, EVS, English, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
3
Board
State, ICSE, CBSE, International Baccalaureate, IGCSE
IB Subjects taught
Hindi, Mathematics, Computers, English, French, Social studies, Science
CBSE Subjects taught
Hindi, French, English, Science, Computers, Mathematics, EVS
ICSE Subjects taught
French, English, Social Studies, Science, Hindi, Mathematics, EVS
IGCSE Subjects taught
English, Mathematics, Science, Hindi
Taught in School or College
No
State Syllabus Subjects taught
English, Mathematics, EVS, Hindi, French, Science, Social Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
ISC/ICSE, International Baccalaureate, State, CBSE, IGCSE
IB Subjects taught
Chemistry, Mathematics
ISC/ICSE Subjects taught
Chemistry, Mathematics
CBSE Subjects taught
Chemistry, Mathematics
IGCSE Subjects taught
Mathematics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Chemistry
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
3
Board
CBSE
CBSE Subjects taught
Chemistry, Mathematics
Taught in School or College
No
1. Which school boards of Class 10 do you teach for?
CBSE
2. Do you have any prior teaching experience?
Yes
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 2 years.
Answered on 28/10/2018 Learn CBSE/Class 11/Science/Chemistry
Calcium carbonate reacts with aqueous HCl according to the reaction
CaC03 (s) + 2HCl (aq) ———->CaCl2 (aq) +C02(g) +H2O(l).
What mass of CaC03 is required to react completely with 25 mL of 0.75 M HCl?
1000 mL of 0.75 M HCl have 0.75 mol of HCl = 0.75×36.5 g = 24.375 g
∴ Mass of HCl in 25mL of 0.75 M HCl = 24.375/1000 × 25 g = 0.6844 g
From the given chemical equation,
CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)
2 mol of HCl i.e. 73 g HCl react completely with 1 mol of CaCO3 i.e. 100g
∴ 0.6844 g HCl reacts completely with CaCO3 = 100/73 × 0.6844 g = 0.938 g
Answered on 25/10/2018 Learn Hydrocarbons
Relative amount of monochlorinated product = Number of hydrogen X relative reactivity For (1°) monochlorinated product = 9x1 = 9
(2°) monochlorinated product = 2x 3.8 = 7.6 (3°) monochlorinated
product = 1x3 = 5
Total amount of monochlorinated compounds = 9 + 7.6+ 5 = 21.6
% of 1° monochlorinated product = 9x100/21.6 =41.67
% of 2° monochlorinated product =7.6x100/21.6 =35.18
% of 3° monochlorinated product =5x100/21.6 =23.15
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
CBSE
CBSE Subjects taught
English, Science, Hindi, Social science, Mathematics
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE
CBSE Subjects taught
English, Science, Hindi, Social science, Mathematics
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
3
Board
IGCSE, State, ICSE, CBSE, International Baccalaureate
IB Subjects taught
Computers, Hindi, Physical Education, English, Science, Mathematics, French
CBSE Subjects taught
Computers, French, EVS, Mathematics, Hindi, English, Social Science, Science
ICSE Subjects taught
Mathematics, English, EVS, Hindi, Computer Science, Geography, Physics, Chemistry, French, History
IGCSE Subjects taught
Hindi, French, English, Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
French, Social science, Hindi, Mathematics, EVS, English, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
3
Board
IGCSE, State, ICSE, CBSE, International Baccalaureate
IB Subjects taught
Computers, Hindi, Physical Education, English, Science, Mathematics, French
CBSE Subjects taught
Computers, French, EVS, Mathematics, Hindi, English, Social Science, Science
ICSE Subjects taught
Mathematics, English, EVS, Hindi, Computer Science, Geography, Physics, Chemistry, French, History
IGCSE Subjects taught
Hindi, French, English, Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
French, Social science, Hindi, Mathematics, EVS, English, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
3
Board
IGCSE, State, ICSE, CBSE, International Baccalaureate
IB Subjects taught
Computers, Hindi, Physical Education, English, Science, Mathematics, French
CBSE Subjects taught
Computers, French, EVS, Mathematics, Hindi, English, Social Science, Science
ICSE Subjects taught
Mathematics, English, EVS, Hindi, Computer Science, Geography, Physics, Chemistry, French, History
IGCSE Subjects taught
Hindi, French, English, Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
French, Social science, Hindi, Mathematics, EVS, English, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
3
Board
State, ICSE, CBSE, International Baccalaureate, IGCSE
IB Subjects taught
Hindi, Mathematics, Computers, English, French, Social studies, Science
CBSE Subjects taught
Hindi, French, English, Science, Computers, Mathematics, EVS
ICSE Subjects taught
French, English, Social Studies, Science, Hindi, Mathematics, EVS
IGCSE Subjects taught
English, Mathematics, Science, Hindi
Taught in School or College
No
State Syllabus Subjects taught
English, Mathematics, EVS, Hindi, French, Science, Social Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
ISC/ICSE, International Baccalaureate, State, CBSE, IGCSE
IB Subjects taught
Chemistry, Mathematics
ISC/ICSE Subjects taught
Chemistry, Mathematics
CBSE Subjects taught
Chemistry, Mathematics
IGCSE Subjects taught
Mathematics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Chemistry
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
3
Board
CBSE
CBSE Subjects taught
Chemistry, Mathematics
Taught in School or College
No
Answered on 28/10/2018 Learn CBSE/Class 11/Science/Chemistry
Calcium carbonate reacts with aqueous HCl according to the reaction
CaC03 (s) + 2HCl (aq) ———->CaCl2 (aq) +C02(g) +H2O(l).
What mass of CaC03 is required to react completely with 25 mL of 0.75 M HCl?
1000 mL of 0.75 M HCl have 0.75 mol of HCl = 0.75×36.5 g = 24.375 g
∴ Mass of HCl in 25mL of 0.75 M HCl = 24.375/1000 × 25 g = 0.6844 g
From the given chemical equation,
CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)
2 mol of HCl i.e. 73 g HCl react completely with 1 mol of CaCO3 i.e. 100g
∴ 0.6844 g HCl reacts completely with CaCO3 = 100/73 × 0.6844 g = 0.938 g
Answered on 25/10/2018 Learn Hydrocarbons
Relative amount of monochlorinated product = Number of hydrogen X relative reactivity For (1°) monochlorinated product = 9x1 = 9
(2°) monochlorinated product = 2x 3.8 = 7.6 (3°) monochlorinated
product = 1x3 = 5
Total amount of monochlorinated compounds = 9 + 7.6+ 5 = 21.6
% of 1° monochlorinated product = 9x100/21.6 =41.67
% of 2° monochlorinated product =7.6x100/21.6 =35.18
% of 3° monochlorinated product =5x100/21.6 =23.15
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Dilsukhnagar, Hyderabad 
