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Soumojit Basak Class 12 Tuition trainer in Kolkata

Soumojit Basak

Physics Enthusiast

Belghoria, Kolkata, India - 700057.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Soumojit Basak✕

Identity

Education

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Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I taught WB Board Madhyamik and class 9 students under my ex private tutor and presently I am teaching a student of class Six of ICSE Board.

Languages Spoken

English

Bengali

Education

Vidyasagar College, under University of Calcutta Pursuing

Bachelor of Science (B.Sc.)

Address

Belghoria, Kolkata, India - 700057

Verified Info

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Teaches

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

1

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

State

ICSE Subjects taught

Chemistry, Physics, Biology, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

1

Board

ICSE, State

ICSE Subjects taught

Chemistry, Physics, Biology, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, State

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

CBSE, ISC/ICSE and State

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 8 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

No, I don't provide a demo class.

5. How many years of experience do you have?

I have been teaching for 1 year.

Contact

Answers by Soumojit Basak (2)

Answered on 23/06/2019 Learn Tuition

if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3

multiply 2 with each side of the equation which means that . After rearranging the terms you get . It implies that that is . So the value of will be either or or . ...more

multiply 2 with each side of the equation which means that . After rearranging the terms you get . It implies that  that is . So the value of   will be either  or  or .

Answers 278 Comments
Dislike Bookmark

Answered on 23/06/2019 Learn Tuition

if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3

Multiply 2 with each side of the eqution i.e. 2(x^2+y^2+z^2)-2(xy+yz+zx)=0. Now rearranging the terms in the above equations, you will get (x-y)^2+(y-z)^2+(x-z)^2=0. It means we get that x=y, y=z, z=x which means x=y=z. So the value of x^3+y^3+z^3 will be either 3x^3 or 3y^3 or 3z^3.
Answers 278 Comments
Dislike Bookmark

Contact

Teaches

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

1

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

State

ICSE Subjects taught

Chemistry, Physics, Biology, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

1

Board

ICSE, State

ICSE Subjects taught

Chemistry, Physics, Biology, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, State

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science

No Reviews yet!

Answers by Soumojit Basak (2)

Answered on 23/06/2019 Learn Tuition

if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3

multiply 2 with each side of the equation which means that . After rearranging the terms you get . It implies that that is . So the value of will be either or or . ...more

multiply 2 with each side of the equation which means that . After rearranging the terms you get . It implies that  that is . So the value of   will be either  or  or .

Answers 278 Comments
Dislike Bookmark

Answered on 23/06/2019 Learn Tuition

if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3

Multiply 2 with each side of the eqution i.e. 2(x^2+y^2+z^2)-2(xy+yz+zx)=0. Now rearranging the terms in the above equations, you will get (x-y)^2+(y-z)^2+(x-z)^2=0. It means we get that x=y, y=z, z=x which means x=y=z. So the value of x^3+y^3+z^3 will be either 3x^3 or 3y^3 or 3z^3.
Answers 278 Comments
Dislike Bookmark

Contact

Soumojit Basak describes himself as Physics Enthusiast. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Soumojit is located in Belghoria, Kolkata. Soumojit takes at students Home and Regular Classes- at his Home. He has 1 years of teaching experience . Soumojit is pursuing Bachelor of Science (B.Sc.) from Vidyasagar College, under University of Calcutta. He is well versed in English and Bengali.

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