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Post a LessonAnswered on 06 Apr Learn Matrices
Sadika
The identity matrix of order n is denoted by I∩
It is a square matrix with dimensions n×nn×n where all the elements on the main diagonal (from the top left to the bottom right) are 1, and all other elements are 0.
Answered on 13 Apr Learn Unit I: Relations and Functions
Nazia Khanum
A relation R:A→AR:A→A is said to be reflexive if, for every element aa in the set AA (where AA is a non-empty set), the ordered pair (a,a)(a,a) belongs to the relation RR. In simpler terms, reflexive relations include every element paired with itself in the set.
Answered on 13 Apr Learn Unit I: Relations and Functions
Nazia Khanum
A relation R:A→AR:A→A is said to be symmetric if for every pair of elements a,ba,b in set AA, whenever (a,b)(a,b) is in RR, then (b,a)(b,a) must also be in RR. In other words, if aa is related to bb, then bb must be related to aa as well, for all a,ba,b in AA.
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Answered on 13 Apr Learn Unit I: Relations and Functions
Nazia Khanum
A universal relation in the context of relational databases refers to a relation (or table) that contains all possible combinations of tuples from the sets involved. In simpler terms, it includes every possible pair of elements from its constituent sets.
For example, let's consider a universal relation that represents the Cartesian product of the sets A = {1, 2} and B = {x, y}. The universal relation would contain all possible combinations of elements from A and B:
Universal Relation: (1, x) (1, y) (2, x) (2, y)
In this example, the universal relation contains all possible combinations of elements from set A and set B.
read lessAnswered on 13 Apr Learn Unit I: Relations and Functions
Nazia Khanum
To prove that the function f:R→Rf:R→R given by f(x)=2xf(x)=2x is one-to-one (injective), we need to show that if f(x1)=f(x2)f(x1)=f(x2), then x1=x2x1=x2 for all x1,x2x1,x2 in the domain.
Let's assume f(x1)=f(x2)f(x1)=f(x2): 2x1=2x22x1=2x2
Now, we'll solve for x1x1 and x2x2: x1=x2x1=x2
Since x1=x2x1=x2, it means that for any two inputs x1x1 and x2x2 that produce the same output under the function f(x)=2xf(x)=2x, those inputs must be the same. This proves that the function f(x)=2xf(x)=2x is one-to-one.
Answered on 13 Apr Learn Unit I: Relations and Functions
Nazia Khanum
To prove that (f+g)∘h=f∘h+g∘h(f+g)∘h=f∘h+g∘h, let's start by understanding what (f+g)∘h(f+g)∘h means:
(f+g)∘h(x)=(f+g)(h(x))=f(h(x))+g(h(x))(f+g)∘h(x)=(f+g)(h(x))=f(h(x))+g(h(x))
Now, let's find (f∘h+g∘h)(x)(f∘h+g∘h)(x):
f∘h(x)+g∘h(x)=f(h(x))+g(h(x))f∘h(x)+g∘h(x)=f(h(x))+g(h(x))
This expression is identical to what we found for (f+g)∘h(x)(f+g)∘h(x). Hence, we can conclude that (f+g)∘h=f∘h+g∘h(f+g)∘h=f∘h+g∘h.
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Answered on 13 Apr Learn Unit I: Relations and Functions
Nazia Khanum
To find (g∘f)(x)(g∘f)(x), which is the composition of g(x)g(x) with f(x)f(x), we substitute f(x)f(x) into g(x)g(x) wherever we see xx.
Given:
f(x)=∣x∣f(x)=∣x∣ g(x)=∣5x+1∣g(x)=∣5x+1∣
We first find f(x)f(x):
f(x)=∣x∣f(x)=∣x∣
And then substitute it into g(x)g(x):
g(f(x))=∣5(∣x∣)+1∣g(f(x))=∣5(∣x∣)+1∣
Now, ∣x∣∣x∣ can be either xx if x≥0x≥0 or −x−x if x<0x<0.
So, ∣5(∣x∣)+1∣∣5(∣x∣)+1∣ will be:
If x≥0x≥0: g(f(x))=∣5x+1∣g(f(x))=∣5x+1∣
If x<0x<0: g(f(x))=∣−5x+1∣g(f(x))=∣−5x+1∣
Answered on 06 Apr Learn Unit III: Calculus
Sadika
Inverse trigonometric functions are functions that "undo" the effects of trigonometric functions. They provide a way to find the angle (or value) associated with a given trigonometric ratio. Inverse trigonometric functions are denoted by \(\sin^{-1}(x)\), \(\cos^{-1}(x)\), \(\tan^{-1}(x)\), \(\cot^{-1}(x)\), \(\sec^{-1}(x)\), and \(\csc^{-1}(x)\), representing arcsine, arccosine, arctangent, arccotangent, arcsecant, and arccosecant, respectively.
Here's a brief explanation of each inverse trigonometric function:
1. **arcsin (or \(\sin^{-1}(x)\))**: Gives the angle whose sine is \(x\), where \(x\) is between -1 and 1.
2. **arccos (or \(\cos^{-1}(x)\))**: Gives the angle whose cosine is \(x\), where \(x\) is between -1 and 1.
3. **arctan (or \(\tan^{-1}(x)\))**: Gives the angle whose tangent is \(x\).
4. **arccot (or \(\cot^{-1}(x)\))**: Gives the angle whose cotangent is \(x\).
5. **arcsec (or \(\sec^{-1}(x)\))**: Gives the angle whose secant is \(x\), where \(x \geq 1\) or \(x \leq -1\).
6. **arccsc (or \(\csc^{-1}(x)\))**: Gives the angle whose cosecant is \(x\), where \(x \geq 1\) or \(x \leq -1\).
It's important to note that the range of inverse trigonometric functions is restricted to ensure that they are single-valued and have unique inverses. The specific range depends on the convention used, but commonly accepted ranges are as follows:
- For arcsin and arccos: \(-\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}\) (or \(-90^\circ \leq \theta \leq 90^\circ\)).
- For arctan: \(-\frac{\pi}{2} < \theta < \frac{\pi}{2}\) (or \(-90^\circ < \theta < 90^\circ\)).
- For arccot: \(0 < \theta < \pi\) (or \(0^\circ < \theta < 180^\circ\)).
- For arcsec and arccsc: \(0 \leq \theta < \frac{\pi}{2}\) and \(\frac{\pi}{2} < \theta \leq \pi\) (or \(0^\circ \leq \theta < 90^\circ\) and \(90^\circ < \theta \leq 180^\circ\)).
These functions are essential in solving trigonometric equations, modeling periodic phenomena, and various applications in science, engineering, and mathematics.
read lessAnswered on 06 Apr Learn Unit III: Calculus
Sadika
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Answered on 06 Apr Learn Unit III: Calculus
Sadika
To determine the principal value of
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