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Post a LessonAnswered on 16 Apr Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Pair of linear equations in two variable
Sadika
Let's denote the speed of the train as T km/h and the speed of the car as C km/h.
According to the given conditions:
Answered on 16 Apr Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Pair of linear equations in two variable
Sadika
To solve the equations graphically, let's first rewrite them in slope-intercept form:&space;\(y&space;=&space;-2x&space;+&space;2\)&space;2.&space;\(2y&space;-&space;x&space;=&space;4\)&space;\(y&space;=&space;\frac{1}{2}x&space;+&space;2\)&space;Now,&space;let's&space;plot&space;these&space;lines&space;on&space;a&space;graph:&space;&space;Now,&space;to&space;find&space;the&space;area&space;of&space;the&space;triangle&space;formed&space;by&space;the&space;two&space;lines&space;and&space;the&space;x-axis&space;(y=0),&space;we&space;need&space;to&space;find&space;the&space;x-coordinates&space;of&space;the&space;points&space;where&space;the&space;lines&space;intersect&space;with&space;the&space;x-axis.&space;For&space;the&space;first&space;line:&space;\[y&space;=&space;-2x&space;+&space;2\]&space;\[0&space;=&space;-2x&space;+&space;2\]&space;\[2x&space;=&space;2\]&space;\[x&space;=&space;1\]&space;For&space;the&space;second&space;line:&space;\[y&space;=&space;\frac{1}{2}x&space;+&space;2\]&space;\[0&space;=&space;\frac{1}{2}x&space;+&space;2\]&space;\[\frac{1}{2}x&space;=&space;-2\]&space;\[x&space;=&space;-4\] "1. \(2x + y=2\) \(y = -2x + 2\) 2. \(2y - x=4\) \(y = \frac{1}{2}x + 2\) Now, let's plot these lines on a graph:  Now, to find the area of the triangle formed by the two lines and the x-axis (y=0), we need to find the x-coordinates of the points where the lines intersect with the x-axis. For the first line: \[y = -2x + 2\] \[0 = -2x + 2\] \[2x = 2\] \[x = 1\] For the second line: \[y = \frac{1}{2}x + 2\] \[0 = \frac{1}{2}x + 2\] \[\frac{1}{2}x = -2\] \[x = -4\]")
Answered on 16 Apr Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Pair of linear equations in two variable
Sadika
To find the value of kk for which the pair of equations has no solution, we need the equations to represent parallel lines.
Answered on 16 Apr Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Arithmetic Progression
Sadika
The difference between any two terms in an arithmetic progression (AP) is constant and equal to the common difference (d).
Answered on 16 Apr Learn CBSE/Class 10/Mathematics/UNIT II: Algebra/Arithmetic Progression
Sadika
In this arithmetic progression, the common difference is
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