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What is the remainder when 39^42 is divided by 10?

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As the whole number is divided by 10 so we need to look only at the units digit of the number i.e. 9^42. As powers of 9 has a cyclicity of 2 meaning odd power of 9 will give 9 as the units digit while even power will give 1. As 9 is raised to power 42 which is even means that the units digit of the...
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As the whole number is divided by 10 so we need to look only at the units digit of the number i.e. 9^42. As powers of 9 has a cyclicity of 2 meaning odd power of 9 will give 9 as the units digit while even power will give 1. As 9 is raised to power 42 which is even means that the units digit of the number will be 1. And 1 ÷ 10 =1 So (39^42)÷10 gives '1' as remainder, which us the desired answer. read less
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39^42 = 39*39*39*39.......till 42 times. 39/10 rem=9. 39^42 => 9^42 is the remainder for the whole part.
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