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Krishan Shetty Class 10 trainer in Thane

Krishan Shetty

Chemistry Tutor

Thane West, Thane, India - 400604.

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Overview

I am a tutor taking classes in chemistry. I have been doing so for the past two years and also a chemical engineer by designation and profession (and have 5 years of experience in that as well). I usually take classes for 9th to 11th standard chemistry.

Languages Spoken

Hindi Proficient

English Proficient

Marathi Proficient

Education

Institute of Chemical Technology, Mumbai 2014

Bachelor of Engineering (B.E.)

Address

Thane West, Thane, India - 400604

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Teaches

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE, ICSE, IGCSE, State, International Baccalaureate

IB Subjects taught

Chemistry

CBSE Subjects taught

Science

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Science

Teaching Experience in detail in Class 10 Tuition

Hi guys, I have 2 years of experience in teaching kids from 9th to 12th standard for CBSE to IB level .

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

International Baccalaureate, IGCSE, ISC/ICSE, CBSE, State

IB Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Chemistry

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE, ICSE, IGCSE, International Baccalaureate

IB Subjects taught

Chemistry

CBSE Subjects taught

Science

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

No

Teaching Experience in detail in Class 9 Tuition

Hi guys, I have 2 years of experience in teaching kids from 9th grade to 12th grade for chemistry subject from CBSE to IB grade.

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

IGCSE, ICSE, International Baccalaureate, CBSE

IB Subjects taught

Science

CBSE Subjects taught

Science

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Science

Taught in School or College

No

Teaching Experience in detail in Class 8 Tuition

Hi guys, I have 2 years of experience in teaching kids from 9th to 12th grade for chemistry and science for CBSE to IB level.

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE, ICSE, IGCSE and others

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 8 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a paid demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Krishan Shetty (3)

Answered on 18/09/2019 Learn CBSE/Class 10/Science/Unit I: Chemical Substances - Nature and Behaviour/Carbon and its compounds/NCERT Solutions/Intext Exercise 4.3

Conversion of ethanol to ethanoic acid is an oxidation reaction because of more oxygen atoms getting attached to the carbon atoms, thus getting the carbon atoms oxidized. And if you burn ethyne in air (79% N2 and 21% O2) instead of 100 % O2, it would not combust completely, thus forming C and CO and... ...more

Conversion of ethanol to ethanoic acid is  an oxidation reaction because of more oxygen atoms getting attached to the carbon atoms, thus getting the carbon atoms oxidized.

 

And if you burn ethyne in air (79% N2 and 21% O2) instead of 100 % O2, it would not combust completely, thus forming C and CO and a resultant sooty flame.

Thats why you need oxy-acetylene( oxy-ethyne) mixture instead of aero-ethyne mixture for welding.

 

Answers 1 Comments
Dislike Bookmark

Answered on 18/09/2019 Learn CBSE/Class 10/Science/Unit I: Chemical Substances - Nature and Behaviour/Carbon and its compounds/NCERT Solutions/Intext Exercise 4.1

Carbon has 4 outermost electrons and both the oxygen atoms have 8 outermost electrons. All the atoms need 8 electrons in its outermost orbit. Both the oxygen atoms will share two of its electrons each to carbon, which will share all of its valnce electrons with botht the O atoms. Thus the electronic... ...more

Carbon has 4 outermost electrons and both the oxygen atoms have 8 outermost electrons.

All the atoms need 8 electrons in its outermost orbit.

 

Both the oxygen atoms will share two of its electrons each to carbon, which will share all of its valnce electrons with botht the O atoms.

 

Thus the electronic dot structure would be 

 

or

Answers 2 Comments
Dislike Bookmark

Answered on 21/08/2019 Learn CBSE/Class 11/Science/Chemistry

There are two ways to solve it: 1) Knowing the mass of one atomic mass unit: Mass of one atomic mass unit = 1.66 * 10^-24 gms Therefore mass of 1000 atoms of nitrogen = Atomic mass of nitrogen * 1000 atoms * Mass of one atomic mass unit = 14 amu/atom * 1000 atoms *1.66 * 10^-24 g/amu = 2.32 * 10^-20... ...more

There are two ways to solve it:

1) Knowing the mass of one atomic mass unit:

Mass of one atomic mass unit = 1.66 * 10^-24 gms

Therefore mass of 1000 atoms of nitrogen = Atomic mass of nitrogen * 1000 atoms * Mass of one atomic mass unit

= 14 amu/atom * 1000 atoms *1.66 * 10^-24 g/amu

= 2.32 * 10^-20 g

2) Knowin mass of one mole of atoms

One mole of nitrogen atoms = 6.022 * 10^23 atoms of nitrogen = 14 g of nitrogen

Therefore 1000 atoms of nitrogen = 14 g/(6.023 *10^23) *1000 atoms = 2.32 * 10^-20 gm

Answers 26 Comments
Dislike Bookmark

Teaches

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE, ICSE, IGCSE, State, International Baccalaureate

IB Subjects taught

Chemistry

CBSE Subjects taught

Science

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Science

Teaching Experience in detail in Class 10 Tuition

Hi guys, I have 2 years of experience in teaching kids from 9th to 12th standard for CBSE to IB level .

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

International Baccalaureate, IGCSE, ISC/ICSE, CBSE, State

IB Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Chemistry

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE, ICSE, IGCSE, International Baccalaureate

IB Subjects taught

Chemistry

CBSE Subjects taught

Science

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

No

Teaching Experience in detail in Class 9 Tuition

Hi guys, I have 2 years of experience in teaching kids from 9th grade to 12th grade for chemistry subject from CBSE to IB grade.

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

IGCSE, ICSE, International Baccalaureate, CBSE

IB Subjects taught

Science

CBSE Subjects taught

Science

ICSE Subjects taught

Chemistry

IGCSE Subjects taught

Science

Taught in School or College

No

Teaching Experience in detail in Class 8 Tuition

Hi guys, I have 2 years of experience in teaching kids from 9th to 12th grade for chemistry and science for CBSE to IB level.

No Reviews yet!

Answers by Krishan Shetty (3)

Answered on 18/09/2019 Learn CBSE/Class 10/Science/Unit I: Chemical Substances - Nature and Behaviour/Carbon and its compounds/NCERT Solutions/Intext Exercise 4.3

Conversion of ethanol to ethanoic acid is an oxidation reaction because of more oxygen atoms getting attached to the carbon atoms, thus getting the carbon atoms oxidized. And if you burn ethyne in air (79% N2 and 21% O2) instead of 100 % O2, it would not combust completely, thus forming C and CO and... ...more

Conversion of ethanol to ethanoic acid is  an oxidation reaction because of more oxygen atoms getting attached to the carbon atoms, thus getting the carbon atoms oxidized.

 

And if you burn ethyne in air (79% N2 and 21% O2) instead of 100 % O2, it would not combust completely, thus forming C and CO and a resultant sooty flame.

Thats why you need oxy-acetylene( oxy-ethyne) mixture instead of aero-ethyne mixture for welding.

 

Answers 1 Comments
Dislike Bookmark

Answered on 18/09/2019 Learn CBSE/Class 10/Science/Unit I: Chemical Substances - Nature and Behaviour/Carbon and its compounds/NCERT Solutions/Intext Exercise 4.1

Carbon has 4 outermost electrons and both the oxygen atoms have 8 outermost electrons. All the atoms need 8 electrons in its outermost orbit. Both the oxygen atoms will share two of its electrons each to carbon, which will share all of its valnce electrons with botht the O atoms. Thus the electronic... ...more

Carbon has 4 outermost electrons and both the oxygen atoms have 8 outermost electrons.

All the atoms need 8 electrons in its outermost orbit.

 

Both the oxygen atoms will share two of its electrons each to carbon, which will share all of its valnce electrons with botht the O atoms.

 

Thus the electronic dot structure would be 

 

or

Answers 2 Comments
Dislike Bookmark

Answered on 21/08/2019 Learn CBSE/Class 11/Science/Chemistry

There are two ways to solve it: 1) Knowing the mass of one atomic mass unit: Mass of one atomic mass unit = 1.66 * 10^-24 gms Therefore mass of 1000 atoms of nitrogen = Atomic mass of nitrogen * 1000 atoms * Mass of one atomic mass unit = 14 amu/atom * 1000 atoms *1.66 * 10^-24 g/amu = 2.32 * 10^-20... ...more

There are two ways to solve it:

1) Knowing the mass of one atomic mass unit:

Mass of one atomic mass unit = 1.66 * 10^-24 gms

Therefore mass of 1000 atoms of nitrogen = Atomic mass of nitrogen * 1000 atoms * Mass of one atomic mass unit

= 14 amu/atom * 1000 atoms *1.66 * 10^-24 g/amu

= 2.32 * 10^-20 g

2) Knowin mass of one mole of atoms

One mole of nitrogen atoms = 6.022 * 10^23 atoms of nitrogen = 14 g of nitrogen

Therefore 1000 atoms of nitrogen = 14 g/(6.023 *10^23) *1000 atoms = 2.32 * 10^-20 gm

Answers 26 Comments
Dislike Bookmark

Krishan Shetty describes himself as Chemistry Tutor. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 8 Tuition. Krishan is located in Thane West, Thane. Krishan takes at students Home and Online Classes- via online medium. He has 2 years of teaching experience . Krishan has completed Bachelor of Engineering (B.E.) from Institute of Chemical Technology, Mumbai in 2014. HeĀ is well versed in Hindi, English and Marathi.

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