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Have been teaching Students of BCA for the Past 2 Years.
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Java Programming Lessons
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Post a LessonAnswered on 17/07/2021 Learn Tuition/BCA Tuition/Java Programming
Kapil Chugh
Assistant Professor (Computer Sci.) with 15+ years of teaching experience
There are some reasons. First, it is open-source. It helps in the fast development of web apps with minimal coding. We can break down the complex work of creating UI components into smaller pieces. Developers can write their apps within JavaScript.
Big companies like Facebook, PayPal, Uber, Instagram, and Airbnb use it to solve user interface related issues.
read lessAnswered on 02/06/2021 Learn Tuition/BCA Tuition/Java Programming
Sangita K.
Dear Sandeep,
You have asked a question that many people ask, and it shows that you have the curiosity in your mind to learn. This era of technology has made it possible for quality courses to be accessible by all. If you want to learn design, code and Data structure, I would suggest taking classes on coding and data structure from the YouTube channel Code With Harry. The courses are for free and are in Hindi. I have referred it to many others, and most of them have been benefited from it.
I wish you luck.
read lessAnswered on 14/05/2021 Learn Tuition/BCA Tuition/Java Programming
Palak Bhalla
Answered on 25/04/2021 Learn Tuition/BCA Tuition/Java Programming
Arunava Biswas
bored of old-schooled teaching? let me show you the millenial way..
this.is my php file:
$con = mysqli_connect($HostName,$HostUser,$password,$db);
// Getting the received JSON into $json variable.
$json = file_get_contents('php://input');
// decoding the received JSON and store into $obj variable.
$obj = json_decode($json,true);
// Populate ID from JSON $obj array and store into $ID.
$ID = $obj['numero'];
//Fetching the selected record.
$CheckSQL = "SELECT origine FROM envoi WHERE numero='$ID'";
$result = $con->query($CheckSQL);
if ($result->num_rows >0) {
while($row[] = $result->fetch_assoc()) {
$Item = $row;
$json = json_encode($Item);
echo $json;
}
}
else {
$EmailExistMSG= "No Results Found.";
$EmailExistJson = json_encode($EmailExistMSG);
echo $EmailExistJson ;
}
And this is my react native script where i should enter number and fetch his data if it's exist in my database:
search= () =>{
//alert('ok');
const {numero}=this.state;
fetch('http://192.168.1.4:80/search.php',{
method:'post',
header:{
'Accept':'application/json',
'Content-type' :'application/json'
},
body:JSON.stringify({numero:numero})}).then((responseData)=>responseData.json()).then((responseJson)=>{alert(responseJson)}).catch((error)=>{console.error(error);})}
render(){
return(
<View style={styles.pass}>
<TextInput placeholder="Saisir le numéro de suivi de l'envoi" onChangeText= {numero=>this.setState({numero})}/>
<TouchableOpacity onPress={this.search} style={{marginTop:20,marginLeft:70}}>
<Icon name="search" size={20}/>
</TouchableOpacity>
</View>
)
}
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