UrbanPro
true

Find the best tutors and institutes for Class 12 Tuition

Find Best Class 12 Tuition

Please select a Category.

Please select a Locality.

No matching category found.

No matching Locality found.

Outside India?

Learn Exercise 9.6 with Free Lessons & Tips

The integrating factor of the differential equation is

A. ex

B. ey

C.

D. x

The given differential equation is:

This is a linear differential equation of the form:

The integrating factor (I.F) is given by the relation,

Hence, the correct answer is C.

Comments

For each of the differential equation given, find the general solution:

This is a linear differential equation of the form:

The general solution of the given differential equation is given by the relation,

Comments

For each of the differential equation given, find the general solution:

The given differential equation is

This is in the form of

The solution of the given differential equation is given by the relation,

Therefore, equation (1) becomes:

This is the required general solution of the given differential equation.

Comments

For each of the differential equation given, find the general solution:

The given differential equation is

The solution of the given differential equation is given by the relation,

This is the required general solution of the given differential equation.

Comments

For each of the differential equation given, find the general solution:

The given differential equation is:

The solution of the given differential equation is given by the relation,

This is the required general solution of the given differential equation.

Comments

For each of the differential equation given, find the general solution:

The given differential equation is:

The general solution of the given differential equation is given by the relation,

Comments

For each of the differential equation given, find the general solution:

The given differential equation is:

This equation is in the form of:

The general solution of the given differential equation is given by the relation,

Therefore, equation (1) becomes:

Comments

For each of the differential equation given, find the general solution:

The given differential equation is:

This equation is in the form of a linear differential equation as:

The general solution of the given differential equation is given by the relation,

Comments

For each of the differential equation given, find the general solution:

The given differential equation is:

This equation is the form of a linear differential equation as:

The general solution of the given differential equation is given by the relation,

Substituting the value of in equation (1), we get:

This is the required general solution of the given differential equation.

Comments

For each of the differential equation given, find the general solution:

This equation is a linear differential equation of the form:

The general solution of the given differential equation is given by the relation,

Comments

For each of the differential equation given, find the general solution:

This equation is a linear differential equation of the form:

The general solution of the given differential equation is given by the relation,

Comments

For each of the differential equation given, find the general solution:

This is a linear differential equation of the form:

The general solution of the given differential equation is given by the relation,

Comments

For each of the differential equation given, find the general solution:

This is a linear differential equation of the form:

The general solution of the given differential equation is given by the relation,

Comments

For each differential equation given, find a particular solution satisfying the given condition:

The given differential equation is

This is a linear equation of the form:

The general solution of the given differential equation is given by the relation,

Now,

Therefore,

Substituting C = –2 in equation (1), we get:

Hence, the required solution of the given differential equation is

Comments

For each differential equation given, find a particular solution satisfying the given condition:

This is a linear differential equation of the form:

The general solution of the given differential equation is given by the relation,

Now, y = 0 at x = 1.

Therefore,

Substituting in equation (1), we get:

This is the required general solution of the given differential equation.

Comments

For each differential equation given, find a particular solution satisfying the given condition:

The given differential equation is

This is a linear differential equation of the form:

The general solution of the given differential equation is given by the relation,

Now,

Therefore, we get:

Substituting C = 4 in equation (1), we get:

This is the required particular solution of the given differential equation.

Comments

Find the equation of a curve passing through the origin given that the slope of the tangent to the curve at any point (xy) is equal to the sum of the coordinates of the point.

Let F (x, y) be the curve passing through the origin.

At point (x, y), the slope of the curve will be

According to the given information:

This is a linear differential equation of the form:

The general solution of the given differential equation is given by the relation,

Substituting in equation (1), we get:

The curve passes through the origin.

Therefore, equation (2) becomes:

1 = C

⇒ C = 1

Substituting C = 1 in equation (2), we get:

Hence, the required equation of curve passing through the origin is

Comments

Find the equation of a curve passing through the point (0, 2) given that the sum of the coordinates of any point on the curve exceeds the magnitude of the slope of the tangent to the curve at that point by 5.

Let F (x, y) be the curve and let (x, y) be a point on the curve. The slope of the tangent to the curve at (x, y) is

According to the given information:

This is a linear differential equation of the form:

The general equation of the curve is given by the relation,

Therefore, equation (1) becomes:

The curve passes through point (0, 2).

Therefore, equation (2) becomes:

0 + 2 – 4 = Ce0

⇒ – 2 = C

⇒ C = – 2

Substituting C = –2 in equation (2), we get:

This is the required equation of the curve.

Comments

The integrating factor of the differential equation.

 is

A.

B.

C.

D.

The given differential equation is:

This is a linear differential equation of the form:

The integrating factor (I.F) is given by the relation,

Hence, the correct answer is D.

Comments

How helpful was it?

How can we Improve it?

Please tell us how it changed your life *

Please enter your feedback

Please enter your question below and we will send it to our tutor communities to answer it *

Please enter your question

Please select your tags

Please select a tag

Name *

Enter a valid name.

Email *

Enter a valid email.

Email or Mobile Number: *

Please enter your email or mobile number

Sorry, this phone number is not verified, Please login with your email Id.

Password: *

Please enter your password

By Signing Up, you agree to our Terms of Use & Privacy Policy

Thanks for your feedback

About UrbanPro

UrbanPro.com helps you to connect with the best Class 12 Tuition in India. Post Your Requirement today and get connected.

X

Looking for Class 12 Tuition Classes?

Find best tutors for Class 12 Tuition Classes by posting a requirement.

  • Post a learning requirement
  • Get customized responses
  • Compare and select the best

Looking for Class 12 Tuition Classes?

Get started now, by booking a Free Demo Class

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more