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Sanjay Krishna Class 11 Tuition trainer in Bangalore

Sanjay Krishna

Mathematics and Physics tutor

Teachers Colony, HSR Layout, Bangalore, India - 560034.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Education

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Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I have tutored students in class 8th and 9th to find out that there is a huge gap between what is taught and what is learn t. Learning enhances the way that you look at the world. Looks into the details we don't understand otherwise. I wish to bring that awareness to a student's mind. My strengths lie in the ability to breakdown large problems into smaller solvable blocks, which i intend to teach. That will enable students to just not see the solution but be able to solve tougher problems by themselves.

Languages Spoken

Malayalam

English

Hindi

Education

Amity University, Noida 2009

Bachelor of Technology (B.Tech.)

Address

Teachers Colony, HSR Layout, Bangalore, India - 560034

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ISC/ICSE, CBSE, IGCSE

ISC/ICSE Subjects taught

Computer Science, Physics, Mathematics

CBSE Subjects taught

Physics, Mathematics, Computer Science

IGCSE Subjects taught

Physics, Mathematics

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ISC/ICSE, CBSE, IGCSE

ISC/ICSE Subjects taught

Computer Science, Physics, Mathematics

CBSE Subjects taught

Physics, Mathematics, Computer Science

IGCSE Subjects taught

Physics, Mathematics

Taught in School or College

No

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, IGCSE, ICSE

CBSE Subjects taught

Science, Computer Practices, Mathematics

ICSE Subjects taught

Computer Application, Mathematics, Physics

IGCSE Subjects taught

Information Technology, Mathematics, Physics

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, IGCSE, ICSE

CBSE Subjects taught

Science, Computer Practices, Mathematics

ICSE Subjects taught

Computer Application, Mathematics, Physics

IGCSE Subjects taught

Information Technology, Mathematics, Physics

Taught in School or College

No

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 12 do you teach for?

ISC/ICSE, CBSE, IGCSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition and Class VI-VIII Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Contact

Answers by Sanjay Krishna (1)

Answered on 05/10/2016 Learn Tuition/Class XI-XII Tuition (PUC) +2 CBSE/Class 12/Mathematics Permutations

How many six digit positive integers that are divisible by 3 can be formed using the digits 0,1,2,3,4,5... ...more
How many six digit positive integers that are divisible by 3 can be formed using the digits 0,1,2,3,4,5 and 6 without any of the digits getting repeating?

Key 1 : Any number whose digits add up to a multiple of 3 is divisible by 3. 6 digit combinations divisible by 3 : A. {0,1,2,3,4,5} => 0+1+2+3+4+5 = 15 (divisible by 3) total number of 6 digit integers formed with the above combination=5*5*4*3*2*1 = 600 B. {1,2,3,4,5,6} => 1+2+3+4+5+6 =... ...more
Key 1 : Any number whose digits add up to a multiple of 3 is divisible by 3. 6 digit combinations divisible by 3 : A. {0,1,2,3,4,5} => 0+1+2+3+4+5 = 15 (divisible by 3) total number of 6 digit integers formed with the above combination=5*5*4*3*2*1 = 600 B. {1,2,3,4,5,6} => 1+2+3+4+5+6 = 21 (divisible by 3) total number of 6 digit integers formed with the above combination=6*5*4*3*2*1 = 720 C. {0,1,2,4,5,6} => 0+1+2+4+5+6 = 18 (divisible by 3) total number of 6 digit integers formed with the above combination=5*5*4*3*2*1 = 600 From A, B and C total number of integers=> 600+720+600 = 1920
Answers 23 Comments
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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ISC/ICSE, CBSE, IGCSE

ISC/ICSE Subjects taught

Computer Science, Physics, Mathematics

CBSE Subjects taught

Physics, Mathematics, Computer Science

IGCSE Subjects taught

Physics, Mathematics

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ISC/ICSE, CBSE, IGCSE

ISC/ICSE Subjects taught

Computer Science, Physics, Mathematics

CBSE Subjects taught

Physics, Mathematics, Computer Science

IGCSE Subjects taught

Physics, Mathematics

Taught in School or College

No

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, IGCSE, ICSE

CBSE Subjects taught

Science, Computer Practices, Mathematics

ICSE Subjects taught

Computer Application, Mathematics, Physics

IGCSE Subjects taught

Information Technology, Mathematics, Physics

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, IGCSE, ICSE

CBSE Subjects taught

Science, Computer Practices, Mathematics

ICSE Subjects taught

Computer Application, Mathematics, Physics

IGCSE Subjects taught

Information Technology, Mathematics, Physics

Taught in School or College

No

No Reviews yet!

Answers by Sanjay Krishna (1)

Answered on 05/10/2016 Learn Tuition/Class XI-XII Tuition (PUC) +2 CBSE/Class 12/Mathematics Permutations

How many six digit positive integers that are divisible by 3 can be formed using the digits 0,1,2,3,4,5... ...more
How many six digit positive integers that are divisible by 3 can be formed using the digits 0,1,2,3,4,5 and 6 without any of the digits getting repeating?

Key 1 : Any number whose digits add up to a multiple of 3 is divisible by 3. 6 digit combinations divisible by 3 : A. {0,1,2,3,4,5} => 0+1+2+3+4+5 = 15 (divisible by 3) total number of 6 digit integers formed with the above combination=5*5*4*3*2*1 = 600 B. {1,2,3,4,5,6} => 1+2+3+4+5+6 =... ...more
Key 1 : Any number whose digits add up to a multiple of 3 is divisible by 3. 6 digit combinations divisible by 3 : A. {0,1,2,3,4,5} => 0+1+2+3+4+5 = 15 (divisible by 3) total number of 6 digit integers formed with the above combination=5*5*4*3*2*1 = 600 B. {1,2,3,4,5,6} => 1+2+3+4+5+6 = 21 (divisible by 3) total number of 6 digit integers formed with the above combination=6*5*4*3*2*1 = 720 C. {0,1,2,4,5,6} => 0+1+2+4+5+6 = 18 (divisible by 3) total number of 6 digit integers formed with the above combination=5*5*4*3*2*1 = 600 From A, B and C total number of integers=> 600+720+600 = 1920
Answers 23 Comments
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Contact

Sanjay Krishna describes himself as Mathematics and Physics tutor. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Sanjay Krishna is located in Teachers Colony, HSR Layout, Bangalore. Sanjay Krishna takes at students Home. Sanjay Krishna has completed Bachelor of Technology (B.Tech.) from Amity University, Noida in 2009. He is well versed in Malayalam, English and Hindi.

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